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A rock is thrown off a cliff at an angle of 46° above the horizontal. The...

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Question

Physics

A rock is thrown off a cliff at an angle of 46° above thehorizontal. The cliff is 120 m high. The initial speed of the rockis 21 m/s. (Assume the height of the thrower is negligible.)

(a)

How high above the edge of the cliff does the rock rise (inm)?

(b)

How far has it moved horizontally when it is at maximum altitude(in m)? m

(c)

How long after the release does it hit the ground (in s)?

(d)

What is the range of the rock (in m)?

(e)

What are the horizontal and vertical positions (in m) of therock relative to the edge of the cliff at

t = 2.0 s,

t = 4.0 s,

and

t = 6.0 s?

(Assume the +x-direction is in the horizontal directionpointing away from the cliff, the +y-direction is uptowards the sky, and x = y = 0 at the point fromwhich the rock is thrown.)

mx(2.0 s)=

my(2.0 s)=

mx(4.0 s)=

my(4.0 s)=

mx(6.0 s)=

my(6.0 s)=

Answer & Explanation Solved by verified expert
3.8 Ratings (568 Votes)
PART AAt the highest point h the vertical velocity becomes zeroieSo the rock rises 11643 m above thecliffPART BThe time    See Answer
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