suppose vol of cytoplasm in cell = 1 litre it means 5% of weight
of solutes = 5/100*1000 = 50 g
O.P.   = molar conc *R*T ....R = 8.314
for proteins ,  molar conc = 10 g/ molecular mass
*1000
              Â
O.P. due to proteins = (10/1000)/45000) * 8.314 * (273+37) =
5.727*10^-4 Pascals
                  Â
\"Â Â Â Â Â Â Â Â Â Â Â
soluble lipids = (10 /400*1000 )*8.314 * (273+37) = 0.0644 \"
                  Â
\"Â Â Â Â Â Â Â Â Â Â
sugars    = (10/170*1000)*8.314*
(273+37)Â Â
=0.1516Â Â Â Â Â Â Â Â Â Â Â Â
\"
                   Â
\"Â Â Â Â Â Â Â Â Â
KCl   =   (20/74.5*1000)
*8.314*(273+37)Â Â =
0.6919Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
\"
