A sample of 0.320 M hydroxylamine (HONH2) is reacted with 0.210
M HBr solution. How many...
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A sample of 0.320 M hydroxylamine (HONH2) is reacted with 0.210M HBr solution. How many mL of the HBr would be required to exactlyneutralize 25.0 mL of the HONH2 solution? answer: 38.10mL. Whatwould be the pH of the solution from part E?
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hydroxylamine HONH2 is a weak base and it reacts with acid like HBr to give salt HONH3Br The reaction is HONH2 HBr HONH3Br So we need 1 mole of HBr for each mole of HONH2 to react to produce 1 mole of acidic salt HONH3Br
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