Original weight of the anchor is
W = dVg
   = 7800 * 2.4 * 9.8
   = 183456 N
Mass of water displaced by the anchor = density of water *
volume of anchor
                                                            Â
= 1000 * 2.4 = 2400 kg
Weight of the water displaced = 2400 * 9.8 = 23520 N
Now the weight of the anchor in water is, W' = 183456 N - 23520
N
                                                                   Â
= 159936 N
So, the change in weight of the anchor is = 183456 - 159936=
23520 N
This means the weight of the dispaced water is equal to
the change in the wieght of the anchor.