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A solution containing a mixture of metal cations was treated with dilute HCl and a precipitate...

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Chemistry

A solution containing a mixture of metal cations was treatedwith dilute HCl and a precipitate formed. The solution was filteredand H2S was bubbled through the acidic solution. A precipitateagain formed and was filtered off. Then, the pH was raised to about8 and H2S was again bubbled through the solution. This time, noprecipitate formed. Finally, the solution was treated with a sodiumcarbonate solution, which resulted in formation of a precipitate.Which metal ions were definitely present, which were definitelyabsent, and which may or may not have been present in the originalmixture? Ag+, Zn2+, Co2+, Li+, Cu2+, Ca2+, Fe2+, Sn2+, Mg2+, Hg22+Sb3+, Hg2+, Pb2+

Answer & Explanation Solved by verified expert
3.6 Ratings (568 Votes)
You can figure out this quesiton by figuring out which of these cations pair with the given anions to form insoluble precipitates If you look up a solubility product chart this will become much easier Ive provided a link below which is one such chart httpmakktfsplithrperiodnienabckpthtml Step 1 You added HCl which is a source of the Cl anion So now its time to look at the chart and find out which of these metals form insoluble metal chloride salts They are AgCl Hg2Cl2 PbCl2 These    See Answer
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