Na2CO3 (aq) + CaCl2 .2H2O(aq) ----------------> 2NaCl (aq) +
CaCO3 (s)
It is given that mixture of Na2CO3 and
CaCl2•2H2O weighs ------------- 4.586g
Let the amount of Na2CO3 ------------------- x g
the amount of CaCl2. 2H2O ----------------------------
(4.586-x)g
From the balanced equation, we get the information that:
106g of Na2CO3 is reacting with------ 147g of CaCl2. 2H2O and
forms---------- 100g of CaCO3
Then ?g of Na2CO3 we
get--------------------------------------------------------------------------
1.356 g of CaCO3
= 1.356g X 106g / 100g
= 1.437g of Na2CO3.
Hence the amount of Na2CO3 in the given mixture x = 1.437g
The amount of CaCl2•2H2O in the given
unknown mixture= 4.586 g - 1.437g
                                                                                        Â
= 3.149g
