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A true breeding red eyed fly with long bristles was crossed to a true breeding white...

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Biology

A true breeding red eyed fly with long bristles was crossed to atrue breeding white eyed fly with stubble bristles. All F1 progenyare red eyed with stubble bristles. An F1 female is crossed to atester male and the following numbers of progeny are observed: 56red eyed, stubble bristles; 72 red eyed, long bristles; 61 whiteeyed stubble bristles; and 68 white eyed, long bristles. You areasked to perform a chi-squared test for this result.

1. What is the best null hypothesis for this test?

2. What is the expected phenotypic ratio?

3. What is the expected number of individuals in each class?

4. What is the calculated Chi-squared value for independentassortment?

5. If the Chi-squared value had been 0.584 (it's not, by theway.) what is the most accurate conclusion?

Answer & Explanation Solved by verified expert
3.7 Ratings (475 Votes)
Answer Cross True breeding red eyed fly with long bristles x true breeding white eyed fly with subble bristles Let Eye Color be represented by R red and r white Let Bristle type be represented as l Long and L stubble All F1 progeny are red eyed with stubble bristles RrLl F1 female RrLl is crossed to a tester male rrll Different gametes formed    See Answer
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