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  3. a volume of 13.96 ml of 0.1060 m naoh solution was

A volume of 13.96 mL of 0.1060 M NaOH solution was used to titrate a 0.618...

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Chemistry

A volume of 13.96 mL of 0.1060 M NaOH solution was used totitrate a 0.618 g sample of unknown containingHC7H5O3.

What is the molecular mass ofHC7H5O3? (report answers to 4 or 5significant figures) 1.3812×102g/mol

What is the percent by mass ofHC7H5O3 in the unknown?

In this problem what mass of sample in grams would be needed todeliver about 23.40 mL in the next trial?

In the second trial above, exactly 1.032 g was transferred into aflask to be titrated. If the initial buret reading is 0.10 mL,predict what the final buret reading be. ?

Answer & Explanation Solved by verified expert
3.9 Ratings (461 Votes)
STEP 1 CALCULATION OF NUMBER OF MOLES OF NAOH IN 1396 mL of 01060 M NaOH SOLUTION 1000 mL of 1 M NaOH contains 1 mol NaOH 1396 mL of 01060 M NaOH contains 1 x 1396 x 01060 1000 x 1 000148 mol NaOH STEP 2 CALCULATION OF NUMBER OF MOLES OF HC7H5O3 IN 0618 g sample of unknown containing HC7H5O3 HC7H5O3 is monoprotic monobasic acid Note that one H atom is wrtten separately Hence    See Answer
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