A wastewater plant with the activated sludge process received 5
× 106 L/day of wastewater with...
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Civil Engineering
A wastewater plant with the activated sludge process received 5× 106 L/day of wastewater with a BOD5 of 500mg/L. The primary clarifier removes 30% of the BOD and primaryclarify effluent has no biomass (Xi=0 mg/L). Recycle(Qr) and waste sludge (Qw) flows are 25% and2% of Qin, respectively. Effluent BOD5 from secondaryclarifier and waste sludge is 20 mg/L. Microorganism concentrationin the waste sludge (Xw) is 6,000 mg/L. SolubleBOD5 is biologically converted into CO2 and Y(yield coefficient) is 0.5 mgVSS /mgBOD
Calculate the value of X and the volume of the tank
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