COD = Chemical oxygen demand
TOC=Total organic carbon .
1) COD= A) ethylene glycol(
C2H6O2)      (12×2+1×6+32)=62
C2H6O2+2.5 O2-→2CO2+3H2O
COD =2.5×32/62×150mg/l= 194mg/l
B) Phenol (C6H6O)     (12×6+1×6+16) =
94
COD= 7×32/94×200mg/l = 476.59mg/l
2) TOC = A) ethylene glycol(
C2H6O2)Â Â Â Â Â Â
(12×2+1×6+32)=62g/mol
Z×12g/mol       Â
2×12=24g/mol                 Â
24g/mol/62g/ml=0.387Â Â
150mg/l×0.387 = 58.05mg/l
B) TOC = Phenol (C6H6O)Â Â Â Â Â
(12×6+1×6+16) = 94g/mol
Carbon mass per mol of satandard compound Z×12 g/mol
6×12gm/mol = 72g/mol
Carbon mass portion of standard compound mass
72gm/mol/94gm/mol= 0.766Â Â Â phenol mass
concentration of standard solution
200gm/l Â
0.766×200mg/l = 153.2mg/l