molarity of H+ = no of moles/volume in L
                       Â
= 1*10-2/10 = 10-3 M
           Â
PHÂ Â = -log[H+]
                   Â
= -log10-3
                   Â
= 3
         Â
[OH-] = Kw/[H+]
                    Â
= 1*10-14/10-3Â Â = 10-11
M
D. solution is acidic solution.
E. [H+] = 10-3/100 = 10-5 M
  PH = -log[H+]
         =
-log10-5
        = 5