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advertisement for this lottery claims that 42 of the population of all the scratchers are winning ones You want to research this claim by selecting a random sample of 48 scratchers Follow the steps below to construct a 95 confidence interval for the population proportion of all winning scratchers Then state whether the confidence interval you construct contradicts the advertisement s claim If necessary consult a list of formulas a Click on Take Sample to see the results from the random sample Take Sample Sample size Point estimate 0 Critical value 0 Compute Winning scratcher Losing scratcher Enter the values of the sample size the point estimate of the population proportion and the critical value you need for your 95 confidence interval Choose the correct critical value from the table of critical values provided When you are done select Compute 0 000 Number 0 000 12 36 Proportion 0 25 0 75 Standard error Margin of error 95 confidence interval 95 confidence interval 0 500 b Based on your sample graph the 95 confidence interval for the population proportion of all winning scratchers Enter the values for the lower and upper limits on the graph to show your confidence interval For the point enter the claim 0 42 from the advertisement X O No the confidence interval does not contradict the claim The proportion 0 42 from the advertisement is inside the 95 confidence interval Critical values No the confidence interval does not contradict the claim The proportion 0 42 from the advertisement is outside the 95 confidence interval 0 005 2 576 20 010 2 326 20 025 1 960 0 050 1 645 0 100 1 282 O Yes the confidence interval contradicts the claim The proportion 0 42 from the advertisement is inside the 95 confidence interval Yes the confidence interval contradicts the claim c Does the 95 confidence interval you constructed contradict the claim from the advertisement Choose the best answer from the choices below S 1 000 1 000 5 A M

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