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An 80 kg skydiver falls through air with a density of 1.15 kg/m3 . Assume that...

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Physics

An 80 kg skydiver falls through air with a density of 1.15 kg/m3. Assume that his drag coefficient is C=0.57. When he falls in thespread-eagle position his body presents an area A1=0.94 m2 to thewind, whereas when he dives head first, with arms close to the bodyand legs together his area is reduced to A2=0.21 m2 . What are theterminal speeds in both cases?

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3.9 Ratings (445 Votes)
An 80kg skydiver falls through air with a density of 115kgm3 Assume that his drag coefficient iscd 057 When he falls in the spreadeagleposition as shown in Figure 421a his body presents an areaA1 094 m2 to the wind whereaswhen he dives head first with arms close to the body and legstogether as shown in Figure 421b his area is reduced toA2 021 m2PROBLEMWhat are the terminal speeds in both casesSOLUTIONWe use equation 414 for the terminal speed and equation 415for the air resistance constant rearrange the formulas and insertthe given numbersThese results show that by diving head first the skydiver canreach higher velocities during free fall than when he    See Answer
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