An alpha particle with kinetic energy 10.5 MeV makes a collisionwith lead nucleus, but it is not \"aimed\" at the center of the leadnucleus, and has an initial nonzero angular momentum (with respectto the stationary lead nucleus) of magnitude L=p0b, where p0 is themagnitude of the initial momentum of the alpha particle andb=1.20×10−12 m . (Assume that the lead nucleus remains stationaryand that it may be treated as a point charge. The atomic number oflead is 82. The alpha particle is a helium nucleus, with atomicnumber 2.)
What is the distance of closest approach?
Repeat for b=1.40×10−13 mm .
Repeat for b=1.20×10−14 mm .
