An alpha particle with kinetic energy 12.0 MeV makes a collisionwith lead nucleus, but it is not \"aimed\" at the center of the leadnucleus, and has an initial nonzero angular momentum (with respectto the stationary lead nucleus) of magnitude L=p0b, where p0 is themagnitude of the initial momentum of the alpha particle andb=1.30×10−12 m . (Assume that the lead nucleus remainsstationary and that it may be treated as a point charge. The atomicnumber of lead is 82. The alpha particle is a helium nucleus, withatomic number 2.)
Part A
What is the distance of closest approach?
Part B
Repeat for b=1.50×10−13 m .
Part C
Repeat for b=1.30×10−14 m .
