Ans:- Compute the cell potential at 25 ∘C.
        Ox: Â
Sn(s)→Sn2+(aq, 1.65 M )+ 2e− : E = -0.14v
         Red:
ClO2(g, 0.165 atm )+ e−→ClO−2(aq, 1.90 M): E = 0.954v
E0 = EC - EA
= 0.954-(-0.14)
= 1.094v
            Â
NERNST EQUTION:Â Â E = E0 -0.0591/2*log
(cathode)/(anode)
                               Â
E = 1.094-0.029*log(1.90)2/(1.65)
  Â
                       Â
E = 1.094-0.029*log 2.1878
                           Â
E = 1.094-0.029*0.34
                           Â
E = 1.0842 Volts