An electron is released from rest at the negative plate of a
parallel plate capacitor and...
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Physics
An electron is released from rest at the negative plate of aparallel plate capacitor and accelerates to the positive plate (seethe drawing). The plates are separated by a distance of 1.4 cm, andthe electric field within the capacitor has a magnitude of 2.0 x10^6 V/m. What is the kinetic energy of the electron just as itreaches the positive plate?
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4.5 Ratings (739 Votes)
Total force acting on electron= qE
                                              Â
=1.6*10-19*2.0*106
                                              Â
=3.2*10-13 N
Change in KE=work done by field=force*displacement
              Â
=3.2*10-13*0.014
              Â
=4.48*10-15 J
Thus final KE of electron=4.48*10-15 J or
27.96*103 eV
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