An enzyme was found that catalyzes the reaction betweenstudents, S and academic success, P (for pass); the enzyme wascalled studyase.
An enzyme assay was run on studyase. 10μg of studyase (molecularweight 20,000D) was placed in a set of test tubes each of whichcontained 1mL of the substrate student at varying concentrationsand the amount of product, academic success (P) was determined.
The following results were determined:
S, (mM) | Velocity, V (μmole/mL/sec) |
1 | 12 |
2 | 20 |
4 | 29 |
8 | 35 |
12 | 40 |
Note 1mM = 1millimole/L = 1μmol/mL
Plot a Lineweaver-Burk plot of 1/V versus 1/S
Determine Vmax and Km for the enzyme studyase.
Calculate Kcat and the catalytic constant (kcat/km) for theenzyme. (find [E]T as total μmoles/mL)
Another enzyme called partyase was analyzed and when 0.010μmoles of this enzyme was assayed it was found to have a Vmax ofabout 50 μmol/mL/sec and a Km of 5 mM. Calculate Kcat and thecatalytic constant for this enzyme.
i.Compare the 2 enzymes on the basisof affinity for the binding site and kinetic efficiency.
