Uncertainity in position   Δx = 2.2 m
(a) according to uncertainity principle
Uncertainity in momentum   ΔP  Â
=   h / (4πΔx)
Here  h = 6.63*10-34 J.s
plug all values we get
         Â
ΔP   =   2.39*10-34 Kg
m/s
(b) mass of the ball  m = 0.045 kg
    Uncetainity in
velocity   ΔV   = Â
ΔP  / m     Â
                  Â
ΔV   = 5.32*10-32 Kg . m/s
(c)  m  = mass of the
electron   =  9.1*10-31
kg
Uncetainity in velocity of the electron Â
    Â
                              ΔV  Â
=  ΔP  / m     =
(Â Â 2.39*10-34 Kg m/s ) /(9.1*10-31
kg   ) Â
                                         Â
Δv  = 2.6210-4 Kg . m/s
