mass of sodium benzoate = 2.00 g
molar mass of sodium benzoate= 144.11 g/mol
moles = mass / molar mass
moles of sodium benzoate (C6H5COONa) = 2 / 144.11
                                                                  Â
= 0.0139
moles of HCl = molarity x volume / 1000
                    Â
= 3 x 5 / 1000
                    Â
= 0.015
C6H5COONa +   HCl  Â
---------------------->Â Â C6H5COOH + NaCl
   1
mol               Â
1 mol
0.0139 mol       0.015 mol
here limiting reagent is C6H5COONa
so 0.0139 mol of HCl is used.
molar equivalents of HCl =
0.01Â Â Â Â Â Â Â Â Â Â Â Â Â Â
(two decimal places)
                      Â
