MgCO3(s)Â Â <--------------------->
MgO(s)+CO2(g)
Kp = PCO2
0.260 = PCO2
moles of MgO = 1 / 40 = 0.025
from
P V = n R T
0.260 x 10 = n x 0.0821 x 650
n = 0.0487
moles of CO2 = 0.0487
MgCO3(s)Â Â <--------------------->
MgO(s)Â Â +Â Â CO2(g)
       1
                                              Â
1Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
1
                                                   Â
0.025Â Â Â Â Â Â Â Â Â
0.0487
here limiting reagent is MgO. so MgCO3 formed based on that.
1 mol of MgO -----------------> 1 mol of MgCO3
0.025 mol of MgO --------------->Â Â ?? MgCO3
moles of MgCO3 = 0.025 x 1 / 1 = 0.025
mass of MgCO3 = moles x molar mass
                         Â
= 0.025 x 84
                        Â
= 2.1 g
