B 3 tan t da 3 sec tdt Now substitute and simplify to get a...
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Calculus
B 3 tan t da 3 sec tdt Now substitute and simplify to get a trig integral in terms of t The trig integral should no longer involve a square root Sv x 9 dx sec Part 2 Evaluating the Trig Integral From previous integration techniques we know that sec t tan t In sec t tan t 2 2 sec t dt tan t 19 sec Use this to evaluate the trig integral from Part 1 and then substitute back to get the final result in terms of x To substitute back in terms of x you would use 9 sec t dt sec t 0 The final result of the integration would then be
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