Calculate [Ag1+] in solution at equilibrium when 2.39 x 10-2 M AgNO3 is added to 1.00...

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Calculate [Ag¹⁺] in solution at equilibrium when 2.39x 10^-2 M AgNO₃ is added to 1.00 L of a 1.65 MNH₃ solution, assuming no volume change? (K_ffor Ag(NH₃)₂¹⁺ is 1.1 x10⁷)
a) 3.8 x 10^-2
b) 2.39 x 10^-2
c) 4.9 x 10^-11
d) 8.5 x 10^-10
e) 4.1 x 10^-3

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4.5 Ratings (766 Votes)

no of moles of AgNo3 = molarity * volume in L

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 2.39*10^-2 *1Â Â = 2.39*10^-2 moles = 0.0239moles

no of moles of NH3Â Â Â Â = molarity * volume in L

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 1.65*1 = 1.65 moles

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Ag⁺Â Â + Â Â 2NH3 ---------> [Ag(NH3)2]⁺

IÂ Â Â Â Â Â Â Â Â Â Â 0.0239 Â Â 1.65 Â Â 0

C -0.0239 Â Â -2*0.0239Â Â Â Â Â Â Â Â Â Â 0.0239

EÂ Â Â Â Â Â Â Â Â Â Â 0Â Â Â Â Â Â Â Â Â Â Â Â Â 1.6022Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0.0239

Â Â Â Â Â Kf =Â Â Â [Ag(NH3)2]⁺/[Ag+][NH3]²

Â Â Â Â 1.1*10⁷Â Â = 0.0239/[Ag+]*0.0239

Â Â Â Â [Ag⁺]Â Â Â Â Â = 0.0239/1.1*10⁷ *0.0239

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 9.1*10^-8 MÂ Â >>>> answer

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Calculate [Ag1+] in solution at equilibrium when 2.39 x 10-2 M AgNO3 is added to 1.00...

Free

70.2K

Verified Solution

Question

Chemistry

Calculate [Ag¹⁺] in solution at equilibrium when 2.39x 10^-2 M AgNO₃ is added to 1.00 L of a 1.65 MNH₃ solution, assuming no volume change? (K_ffor Ag(NH₃)₂¹⁺ is 1.1 x10⁷)
a) 3.8 x 10^-2
b) 2.39 x 10^-2
c) 4.9 x 10^-11
d) 8.5 x 10^-10
e) 4.1 x 10^-3

Answer & Explanation Solved by verified expert

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Calculate [Ag1+] in solution at equilibrium when 2.39 x 10-2 M AgNO3 is added to 1.00...

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70.2K

Verified Solution

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Chemistry

Calculate [Ag1+] in solution at equilibrium when 2.39x 10-2 M AgNO3 is added to 1.00 L of a 1.65 MNH3 solution, assuming no volume change? (Kffor Ag(NH3)21+ is 1.1 x107)a) 3.8 x 10-2b) 2.39 x 10-2c) 4.9 x 10-11d) 8.5 x 10-10e) 4.1 x 10-3

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Calculate [Ag¹⁺] in solution at equilibrium when 2.39x 10^-2 M AgNO₃ is added to 1.00 L of a 1.65 MNH₃ solution, assuming no volume change? (K_ffor Ag(NH₃)₂¹⁺ is 1.1 x10⁷)
a) 3.8 x 10^-2
b) 2.39 x 10^-2
c) 4.9 x 10^-11
d) 8.5 x 10^-10
e) 4.1 x 10^-3