A. pH = 2.52
POHÂ Â = 14-PH
         =
14-2.52
POH Â Â Â = 11.48
-log[OH^-] = 11.48
    [OH^-]   =
10^-11.48Â Â = 3.3*10^-12M
B. pH = 8.09
POH = 14-PH
         =
14-8.09
POH Â Â Â = 5.91
-log[OH^-] = 5.91
    [OH^-]  = 10^-5.91
                    Â
= 1.23*10^-6M
C. pH = 13.58
POHÂ Â = 14-PH
          Â
= 14-13.58
            Â
= 0.42
-log[OH^-] = 0.42
      [OH^-]  =
10^-0.42
                 Â
= 0.38M