Calculate the concentration of all species present in a 0.01 M aqueous solution of ammonia. The...

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Calculate the concentration of all species present in a 0.01 Maqueous solution of ammonia. The pKa of the ammonium ion is9.24.
A.)Calculate [H⁺] (express the result in molar unitsusing three significant figures and scientific notation).
B.)Calculate [OH^-] (express the result in molar unitsusing three significant figures and scientific notation).
C.)Calculate [NH+4]Â Â (express theresult in molar units using three significant figures andscientific notation).
D.)Calculate [NH3]Â Â (express theresult in molar units using three significant figures andscientific notation).
E.)What is the pH of the solution?

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4.5 Ratings (591 Votes)

Â Â Â Â Â Â Â Â Â Pka + Pkb = 14

Â Â Â Â Â Â Â Â Â PkbÂ Â Â Â Â Â Â Â Â Â Â Â Â Â = 14-Pka

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 14-9.24

Â Â Â Â Â Â Â Â Â Â PKbÂ Â Â Â Â Â Â Â Â Â Â = 4.76

Â Â Â Â Â Â Â Â Â -logKbÂ Â Â Â Â Â Â = 4.76

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â KbÂ Â Â Â Â Â = 10^-4.76

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 1.74*10^-5

Â Â Â Â NH3 + H2O ---------> NH4⁺ + OH^-

IÂ Â Â Â Â Â Â 0.01Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 0Â Â Â Â Â Â Â Â 0

CÂ Â Â -xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â +xÂ Â Â Â Â Â +x

EÂ Â Â 0.01-xÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â +xÂ Â Â Â Â Â +x

Â Â Â Kb = [NH4+][OH-]/{NH3]

Â Â 1.74*10^-5 = x*x/0.01-x

1.74*10^-5 *(0.01-x) = x²

Â Â Â Â Â Â Â Â Â x = 0.00041

[NH4+] =x = 0.000408M

[OH-]Â Â Â = xÂ Â = 0.000408M

{NH3]Â Â = 0.01-x = 0.01-0.000408 = 0.00959M

[H+]Â Â = Kw/[OH-]

Â Â Â Â Â Â Â Â Â Â = 1*10^-14/0.000408

Â Â Â Â Â Â Â Â Â Â =2.45*10^-11 M

E. PH = -log[H+]

Â Â Â Â Â Â Â Â Â Â Â = -log2.45*10^-11

Â Â Â Â Â Â Â Â Â Â = 10.61

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Calculate the concentration of all species present in a 0.01 M aqueous solution of ammonia. The...

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