calculate the mass in grams of 7.88 mol of RbMnO4

4.2 Ratings (533 Votes)

mol = weight of the compound in grams / molar mass of the compound in grams / mol

molar mass = sum of weight of individual atoms in g /mol

molar mass of RbMnO4 = (1 X 85.4678) + (1 X 54.938045) + (4 X 15.9994)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 204.4034 g/mol

weight of the compound in grams = mol X molar mass of the compound in grams / mol

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 7.88 mol X 204.4034 g/mol

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 1610.698792 g

The mass in grams of 7.88 mol of RbMnO4 = 1610.698792 grams

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