Data:
Hole depth, Lh = 5 3/8 = 5.375 in , Drill dia / hole
dia, D = 2.25in,
              Â
                              Â
Cutting time = 0.5 hr = 30 min   Â
Soln:
Length of cut, Lc = 5 3/8 + 1/2 = 5.875 in
Cycle time, Tc = Lc / (f * N)
i.e., (f*N) = Lc / Tc = 5.875 / 30 = 0.196 in /min
Now, The material removal rate is MRR = (?D2 / 4)
(f*N)
MRR =Â Â (?*2.252 / 4) (0.196) =0.78
in3/min
MRR = 0.78
in3/min OR 0.013 in3/s
