CALCULATE THE NUMBER OF FRENKEL DEFECTS PRESENT IN A CRYSTAL OF AgCl at 300 K, GIVEN...

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CALCULATE THE NUMBER OF FRENKEL DEFECTS PRESENT IN ACRYSTAL OF AgCl at 300 K, GIVEN THAT THE MATERIAL HAS A CUBE UNITCELL OF EDGE 0.555 nm THAT CONTAINS 4 A g ATOMS. ASSUME THAT THEINTERSTITIAL ATOMS OCCUMY ANY OF 8 TETRAHEDRAL SITES IN THE UNITCELL. Hf = 2.69 x 10^-19 L

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number of Frankel defects = (square root of ( N * Ni)) * e^(-dH/2RT)

N = number of atoms present in unit cell

Ni = number of interstial positions

dH = enthalpy of formation for frankel defect

R = gas constant

T = absolute temperature

Number of Frankel defects = (square root of ( N * Ni)) * e^(-dH/2RT)

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = (square root of (4 * 8)) * e^((2.69*10^-19)/(2*8.314*300))

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â = 1

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CALCULATE THE NUMBER OF FRENKEL DEFECTS PRESENT IN A CRYSTAL OF AgCl at 300 K, GIVEN...

Free

80.2K

Verified Solution

Question

Chemistry

CALCULATE THE NUMBER OF FRENKEL DEFECTS PRESENT IN ACRYSTAL OF AgCl at 300 K, GIVEN THAT THE MATERIAL HAS A CUBE UNITCELL OF EDGE 0.555 nm THAT CONTAINS 4 A g ATOMS. ASSUME THAT THEINTERSTITIAL ATOMS OCCUMY ANY OF 8 TETRAHEDRAL SITES IN THE UNITCELL. Hf = 2.69 x 10^-19 L

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