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Calculate the percent ionization of arsenous acid (H3AsO3) in solutions of each of the following concentrations (Ka...

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Chemistry

Calculate the percent ionization of arsenous acid(H3AsO3) in solutions of each of thefollowing concentrations (Ka = 5.1e-10.)



(a) 0.206 M

%



(b) 0.556 M

%



(c) 0.822 M

%

Answer & Explanation Solved by verified expert
4.5 Ratings (577 Votes)

The relation between percent ionization a , Ka and C is Ka = Ca2

Then ,

   a = (Ka/C)1/2

Given that Ka of H3AsO3 = 5.1 x 10-10

a)    C = 0.206 M

      a = (Ka/C)1/2

             = (5.1 x 10-10/0.206)1/2

         = 0.000049

        = 0.0049 %

Therefore,

percent ionization = 0.0049 %

b)    C = 0.556 M

      a = (Ka/C)1/2

             = (5.1 x 10-10/0.556)1/2

         = 0.00003

        = 0.003 %

Therefore,

percent ionization = 0.003 %

c)    C = 0.822 M

      a = (Ka/C)1/2

             = (5.1 x 10-10/0.822)1/2

         = 0.000025

        = 0.0025 %

Therefore,

percent ionization = 0.0025 %
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