HBrO ßà H+ + BRO-
CÂ Â Â Â Â Â Â Â Â Â Â
0Â Â Â Â Â Â Â 0Â Â
(initial)
C-x         Â
x      x (at
equilibrium)
Ka = x*x / (C-x)
since Ka is very small, x will be small and can be
ignored as compared to C
Above expression will thus become,
Ka = x*x / C
x = sqrt (Ka*C)
percent ionization = x*100/C
                 Â
=(100/C) sqrt (Ka*C)
a)
percent ionization = (100/0.263)*sqrt(2.5*10^-9 *
0.263)
                 Â
= 0.00975 %
b)
percent ionization = (100/0.477)*sqrt(2.5*10^-9 *
0.477)
                 Â
= 0.00724 %
c)
percent ionization = (100/0.868)*sqrt(2.5*10^-9 *
0.868)
                 Â
= 0.00537 %
