Calculate the pH after 0.017 mole of HCl is added to 1.00 L of
each of...
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Chemistry
Calculate the pH after 0.017 mole of HCl is added to 1.00 L ofeach of the four solutions. (Assume that all solutions are at25°C.) (a) 0.128 M butanoic acid (HC4H7O2, Ka = 1.5 ✕ 10−5) (b)0.128 M sodium butanoate (NaC4H7O2) (c) pure H2O (d) 0.128 MHC4H7O2 and 0.128 M NaC4H7O2
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a concentration of HCl in 1L solution 0017 mol 1L 0017 M HCl is a strong acid and it is completely dissociated to form Haq ion Hence concentration of Haq due to HCl 0017 M Dissociation of butanoic acid also produces H ion that can be calculated as C4H8O2
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