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Calculate the pH of a solution composed of 0.50 M NH3 and 0.20 M NH4Cl. Kb...

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Chemistry

Calculate the pH of a solution composed of 0.50 M NH3 and 0.20M NH4Cl. Kb NH3 = 1.8 x 10-5

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4.0 Ratings (448 Votes)

               PKb   = -logKb

                        = -log1.8*10-5

                        = 4.75

     POH    = PKb + log[NH4Cl]/[NH3]

               = 4.75 + log0.2/0.5

               = 4.75 -0.3979

               = 4.3521

     PH   = 14-POH

             = 14-4.3521   = 9.6479 >>>> answer
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