Ka of JClO= 4*10-8
ICE table  Â
             Â
HClOÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
H+Â Â Â Â Â Â Â ClO-
initial                          Â
0.25Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
0Â Â Â Â Â Â Â Â Â Â Â Â
0
Change                     Â
-x                           Â
x            Â
x
Ka= x2/(0.25-x)= 4*10-8 whem solved using
excel, [H+] =1*10-4, pH= 4
2. Sr(OH)2----> Sr+2 + 2OH-
Strontium hydroxixe is strong base
hecne 0.015M gives rise to 2*0.015=0.03M OH-
pOH= -log(0.03)=1.523, pH= 14-1.523 =12.477
3. HI is strong acid hence [H+] =0.015, pH= -log(0.015)=
1.823
4. Kb of CH3NH2= 4.4*10-4
CH3NH2+ H2O----->CH3NH3+ + OH-
Kb= [CH3NH3+] [OH-]/[CH3NH2] = x2/ (0.15-x)=
4.4*10-4,  x= 0.0076 when solved using
excel
pOH= -log(0.0076)= 2.12, pH= 14-2.12= 11.88
