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Calculate the pH of the solution after the addition of the following amounts of 0.0568 M...

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Chemistry

Calculate the pH of the solution after the addition of thefollowing amounts of 0.0568 M HNO3 to a 80.0 mL solution of 0.0750M aziridine. The pKa of aziridinium is 8.04.

a) 0.00 mL of HNO3

b) 8.62 mL of HNO3

c) Volume of HNO3 equal to half the equivalence point volume

d) 102 mL of HNO3

e) Volume of HNO3 equal to the equivalence point

f) 89.2 mL of HNO3

thank you

Answer & Explanation Solved by verified expert
4.3 Ratings (949 Votes)
Here pKa 804 Concentration of aziridine 00750 M We have pKa log Ka Therefore Ka 10pKa 10804 912 x 109 Also Kb Kw Ka 1014 912X109 11 x 106 Part a 000 mL of HNO3 is added Constructing the ICE C2H5N H2OC2H6N OH Initial 00750 0 0 Final 00750x xx Kb C2H6N OH C2H5N 11 x 106 xxx 00750x Here x is small compared to 0075 Therefore x can    See Answer
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