Calculate the vapour pressure lowering of a 1M aqueous sucrose(sugar) solution at 25 oC where po(H2O) = 23 mm Hg. The density of1M sucrose at 25 oC is 1.129 g/mL.
The answer to this question is 0.51 mm Hg
Can you please explain how ti find this?
We know that vapour pressure lowering is DeltaP = X_b * P_A
but how do i find the mole fraction?
Can some one please explain this in detail
Thank you
