Calculate the volume of 0.820-M NaOH solution needed to completely neutralize 112 mL of a 0.620-M solution...

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Calculate the volume of 0.820-M NaOH solutionneeded to completely neutralize 112 mL of a0.620-M solution of themonoprotic acid HCl.
__________ mL NaOH

Answer & Explanation Solved by verified expert

3.8 Ratings (564 Votes)

As both NaOH and HCl case, Molarity = Normality

N_base x V_base = N_acid X V_acid

N_base = 0.82 M and V_base = ?

Similarily, N_acid = 0.62 M and V_acid = 112 mLÂ Â Â (given)

From above relation: 0.82 X V_base = 0.62 x 112

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â V_base = 0.62 x 112 / 0.82

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â V_base = 69.44 / 0.82

Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â V_base = 84.68 mL

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Calculate the volume of 0.820-M NaOH solution needed to completely neutralize 112 mL of a 0.620-M solution...

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70.2K

Verified Solution

Question

Chemistry

Calculate the volume of 0.820-M NaOH solutionneeded to completely neutralize 112 mL of a0.620-M solution of themonoprotic acid HCl.
__________ mL NaOH

Answer & Explanation Solved by verified expert

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Calculate the volume of 0.820-M NaOH solution needed to completely neutralize 112 mL of a 0.620-M solution...

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Chemistry

Calculate the volume of 0.820-M NaOH solutionneeded to completely neutralize 112 mL of a0.620-M solution of themonoprotic acid HCl.__________ mL NaOH

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Calculate the volume of 0.820-M NaOH solutionneeded to completely neutralize 112 mL of a0.620-M solution of themonoprotic acid HCl.
__________ mL NaOH