Density of vinegar = 1.01g/ml
assume volume of vinegar = 1L = 1000ml
mass of vinegar = density * volume in ml
                      Â
= 1.01*1000 = 1010gm
molarity of acetic acid = 0.8488M
assume volume of acetiv acid = 1L
no of moles of acetic acid = molarity *volume in L
                                     Â
= 0.8488*1 = 0.8488moles
mass of acetic acid       =
no of moles * G.M.Wt
                                Â
= 0.8488*60 = 50.928gm
mass percentage of acetic acid = mass of acetic acid*100/mass of
vinegar
                                               Â
= 50.928*100/1010
                                                Â
= 5.04%
percentage error = Actual mass- calculated mass*100/actual
mass
But actual mass not given
