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Candy chemist was asked to determine the concentration (m/m) of new alcoholic beverage from the molarity,...

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Chemistry

Candy chemist was asked to determine the concentration (m/m) ofnew alcoholic beverage from the molarity, which was determined tobe 3.205 M and the density, which was found to be .984 g/mL/ Whatis the mass percent of ethanol (MM= 46.068 / mol) in the beverage?

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3.6 Ratings (406 Votes)

                                 Molarity= { [(w/W)%] X10Xd} x[1/M.wt]

Molarity= 3.205        denisity= 0.984               M.wt= 46.08   

                                  Molarity= { [(w/W)%] X10Xd} x[1/M.wt]

                                   3.025 = { [(w/W)%] x10x0.984x[1/46.08]

                               w/W%=    [3.025x46.08]/[9.84]

   w/W%=    [139.39]/[9.84]

                                          =14.165%

                  
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