construct the ICE table
here we donot want to consider the concentration of C because it
is solide and it is excess
          Â
S2 (g)Â Â + C (s) <----> CS2 (g)
IÂ Â Â Â Â Â Â Â Â Â Â Â
12.4Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
0
CÂ Â Â Â Â Â Â Â Â Â Â
-x                               Â
+x
EÂ Â Â Â Â Â Â Â Â Â Â Â
12.4-x                        Â
+x
now equilibrium expression Kc
Kc = [CS2] / [S2]
9.40 = 12.4-x / x
9.4x = 12.4-x
10.4x = 12.4
x = 12.4 / 10.4
x = 1.1923 moles  = [CS2]
grams of CS2 = moles of CS2 x molar mass x CS2
= 1.1923 grams x 76.14 gram/mole
=90.7823 grams
