Chemistry: Calorimetry and Heats of Reaction
Mass of water in styrofoam cup: 100g
Mass of KCl: 1.650g
Initial Temperature: 20.6degC
Final Temperature: 19.6degC
q=(75g)(1.0 cal/g x degC)(-1degC)= -75cal
qreaction= -qcontents
-75 cal = 75 cal --> 0.075kCal
1.650g KCl = 0.2214 mol KCl
0.075kCal/0.02214mol = 3.39kCal mol KCl
Is this the standard heat of solution?
If this is the standard heat of solution, how would I determinethe percent error of my result?
I was given this equation:
Percent error = |lit value - exptl value/lit value| x 100
with this information:
KCl(s) --> K+(g) + Cl-(g) dH=167.1kCal/mol
K+(g) + Cl-(g --> dH=163.0 kCal/mol
KCl(s) --> K+(aq) + Cl-(aq) dH=??
I know this question was super long. I'm sorry I'm confused andI'm not really sure where to begin.
