Complete the following nuclear equations:
When doing these equations you are obeying the law ofconservation of mass and charge. What this means is that the sum oftop numbers (masses) on the left side must equal the sum of themasses on the right. It also means the sum of the bottom numbers(charges) on the left equal the sum of the charges on the right.The charge (atomic number) of the isotope determines the element.Look on the periodic table to find the identity of the element.
- 8Li3Ã oe-1 + 4He2 +_____
- 32P15Ã 0e-1+ ________
- 60Co27Ã 0e-1 + ______
- 97Tc43 +0e-1Ã _______
- 99Tc43Ã b + _______
- 239Pu94Ã a+ ____
- 1H1 +14N7Ã ________+ a
- Â Â 3He2 +3He2Ã 21H1 + ______
- 2 1H1Ã 2H1 + _____
- 1p1 +12C6Ã _________
- ________+ aà 243Bk97 +1n0
- 238U92 +12C6Ã ______ + 6 neutrons
- 249Cf98 +_______Ã 263Sg106 + 4 neutrons
- 249Cf98 +10B5Ã 257Lr103 + ______
- 238U92Ã 4He2+ _____
- 14C6à β + ________
- 235U92--Ã _________ + 4 neutrons
- 5Li3-à α + ______
- 208Pb82-à α + ______
- 63Cu29 +2H1Ã 21n0 + _____
- 44Ca20 +1H1Ã 44Sc21 + _____
- 9Be4 +α à 12C6 +______
- 31P15 +2H1Ã 32P15 + _____
- 37Cl17 +_____ à 35S16 + α
- 2H1 +2H1Ã 1H1 + _____
- 11B5 +4He2Ã 14N7 + ____
- 63Cu29 +2H1Ã 64Zn30 + ____
- 239Pu94 +α à 1n0 +______
- 63Cu29 +1H1Ã 38Cl17 + 1n0 +____
- 235U92 +1n0Ã 95Mo42 + 21n0 +_____
- ____________à 237Np93+ α
- 122Sb51 +α à ______
- 23Na11+αà 26Mg12 +_____