| Sodium thiosulfate concentration(M) |
0.051M |
| Volume calcium iodate used(L ) |
0.01L |
| Thiosulfate solution volume |
0.01814L |
| moles of thiosulfate used |
0.00092514 |
| moles of Iodate |
0.00015419 |
| Equillibrium concentration of Iodate ion(M) |
0.005479M |
| Equillibeium conecentration of calcium ion(M) |
0.0027395M |
| Molar solubility of Calcium Iodate |
0.0027395 mol/L |
| Ksp of calcium Iodate |
8.22×10-8 |
Explanation
i) IO3- (aq) + 6S2O32-(aq) +
6H3O+(aq) ------> I-(aq) +
3S4O62-(aq) + 9H2O(l)
Stoichiometrically , 6 moles of S2O32-reacts with
1mole of IO3-
Therefore,
Number of moles of IO3- = Number of moles of
S2O32-/6
ii) Total volume = 0.01L + 0.01814L = 0.02814L
Equillibrium concentration of IO3- =
0.00015419mol/0.02814m = 0.005479M
iii)Equillibrium concentration of Ca+ = 0.005479M/2 =
0.0027395M
iv) Molar solubility of Ca(IO3)2 = Concentration of
Ca2+
v) Ksp =
[Ca2+][IO3-]2
=
(0.0027395M)×(0.005479M)2
= 8.22×10-8
M
