Consider the titration of 20.0 mL of 0.0800 M C5H5N (a weak
base; Kb = 1.70e-09)...
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Consider the titration of 20.0 mL of 0.0800 M C5H5N (a weakbase; Kb = 1.70e-09) with 0.100 M HCl. Calculate the pH after thefollowing volumes of titrant have been added:
(a) 0.0 mL pH =
(b) 4.0 mL pH =
(c) 8.0 mL pH =
(d) 12.0 mL pH =
(e) 16.0 mL pH =
(f) 22.4 mL pH =
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3.6 Ratings (413 Votes)
millimoles of pyridine 20 x 008 16 kb 17x109 pKb logKb log 17x109 877 a before the addition of any HCl pOH 12 pKb logC 12 877 log0100 488 pH pOH 14 pH 912 b after the
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