Consider the titration of a 26.0-mL sample of 0.180 M CH3NH2with 0.145 M HBr. (The value of Kb for CH3NH2 is4.4×10−4.)
Already found:
volume of added acid required to reach the equivalencepoint.=32.3 ml
pH at 6.0 mL of added acid=11.28
pH at one-half of the equivalence point.= 10.64
Part A
Determine the initial pH
Part B
Determine the pH at the equivalence point.
Part C
Determine the pH after adding 5.0 mL of acid beyond theequivalence point.