Cultivated amaranth grains (Amaranthus caudatus) come in threecolors: black, brown, and pale. Geneticists asked whether thisphenotype could result from a dominant epistatic control. Crossingblack-seeded and pale-seeded A. caudatus populations (homozygouslines) gave the following counts of black, brown, and pale seeds inthe second generation (F2).
Seed coat color | Black | Brown | Pale |
Seed count | 344 | 82 | 31 |
In genetics, dominant epistasis should lead to 12/16 of all suchseeds being black, 3/16 Brown, and 1/16 pale. Do the experimentaldata above support the conclusion that seed coat color incultivated amaranth grains is due to dominant epistasis?
Please find the Ho, Ha, test statistic, df, exact probability ofthe test statistic, and conclusion relative to the hypothesis. Isthis a 1-tailed or 2-tailed test? Use Excel functions and mathcalculations, please.
I think you Chi-Squared for this, but I am not sure.
