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Determine the Ph 0.120 M NaClO and 4.50×10−2 M KI Express your answer using two decimal places.

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Chemistry

Determine the Ph

0.120 M NaClO and 4.50×10−2 M KI

Express your answer using two decimal places.

Answer & Explanation Solved by verified expert
3.7 Ratings (645 Votes)

KI is a slat of strong HI and strong base . so it will not produce H+ and OH- , so no effect on PH

NaClO----------> Na+ + OCl-

OCl- + H2O -------> HoCl + OH-

I        0.12                               0          0

C -x                                   +x           +x

E    0.12-x                            +x          +x

        Kb = [HOCl][OH-]/[OCl-]

       Kb = Kw/Ka

            = 1*10-14/3*10-8

              = 3.3*10-7

    Kb = [HOCl][OH-]/[OCl-]

   3.3*10-7        =   x*x/0.12-x

    3.3*10-7*(0.12-x) = x2

                x   = 0.000198

[OH-] = x = 0.000198M

   POH = -log[OH-]

           = -log0.000198

           = 3.703

   PH = 14-POH

          = 14-3.703

         = 10.297 >>>> answer

   
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