KI is a slat of strong HI and strong base . so it will not
produce H+ and OH- , so no effect on PH
NaClO----------> Na+ + OCl-
OCl- + H2O -------> HoCl + OH-
IÂ Â Â Â Â Â Â
0.12Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â
0Â Â Â Â Â Â Â Â Â 0
C
-x                                 Â
+x         Â
+x
E Â Â
0.12-x                          Â
+x         +x
       Kb =
[HOCl][OH-]/[OCl-]
      Kb = Kw/Ka
          Â
= 1*10-14/3*10-8
            Â
= 3.3*10-7
   Kb = [HOCl][OH-]/[OCl-]
  3.3*10-7
      =  x*x/0.12-x
   3.3*10-7*(0.12-x) =
x2
              Â
x  = 0.000198
[OH-] = x = 0.000198M
  POH = -log[OH-]
          =
-log0.000198
          =
3.703
  PH = 14-POH
         =
14-3.703
        = 10.297
>>>> answer
  Â
