KHC8H4O4 (aq) + NaOH(aq) ------------->
NaKC8H4O4 + H2O
1
mole                   Â
1mole
no of moles of KHPÂ Â = W/G.M.Wt
                               Â
= 0.3001/204.263Â Â = 0.00147 moles
1 mole of KHP react with 1 mole of NaOH
0.00147 moles of KHP react with 0.00147 moles of NaOH
no of moles of NaOHÂ Â = molarity * volume in L
              Â
0.00147Â Â Â Â Â Â Â = molarity *
0.01354
         Â
molarity         Â
= 0.00147/0.01354Â Â Â = 0.109M
molarity of NaOH = 0.109M
