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  3. encipher each plaintext trigraph code by computing

Encipher each plaintext trigraph code by computing (Plaintext trigraph code)Public Key, dividing the result by the Modulus...

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  • Encipher each plaintext trigraph code by computing(Plaintext trigraph code)Public Key,dividing the result by the Modulus and taking theremainder.

Okay so the trigraph key is 2723 and the public key is 97 andthe modulus is 50657. Literally every calculator i use says thenumber is too large. I am so confused. These are the numbers whatis the problem. Is this the wrong formula the teacher gave us thisformula. I am so confused.

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