Explain and solve the following physics question.
An alpha particle with kinetic energy 14.0 MeV makes a collisionwith lead nucleus, but it is not \"aimed\" at the center of the leadnucleus, and has an initial nonzero angular momentum (with respectto the stationary lead nucleus) of magnitudeL=p0b, where p0 is themagnitude of the initial momentum of the alpha particle andb=1.20×10−12 m . (Assume that the lead nucleusremains stationary and that it may be treated as a point charge.The atomic number of lead is 82. The alpha particle is a heliumnucleus, with atomic number 2.)
1. What is the distance of closest approach? Find r.(meters)
2. Repeat for b =1.30×10−13 m. Find r.(meters)
3. Repeat for b =1.30×10−14 m. (meters)
