Figure shows the displacement time graph of a particle executing SHM with a time period...
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Figure shows the displacement time graph of a particle executing SHM with a time period T Four points 1 2 3 and 4 are marked on the graph where the displacement is half that of the amplitude A 2 0 A 2 A Ap 2 T a Identify the points of same displacement but with opposite direction of motion Find the time difference between them 2 b Identify the points where the particles move in the same direction Find the time difference between them T 4 Sol a Points 1 and 2 have same displacements x 4 2 with equal but opposite velocities Similarly points 3 and 4 have same displacements x A 2 with equal but opposite velocities The phase difference between 1 and 2 and 3 and 4 is t 3 Therefore the time difference is T 27
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